Homework # 10 - Math 149
The problems on this homework must be done alone. The honor code is in effect.
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For questions 1 - 5, take the derivative.
1. \(f(x) = \ln(\ln(\ln x ))\)
a. \( f'(x) = \frac{1}{x^3}\)
b. \( f'(x) = \frac{1}{(\ln x)^3}\)
c. \( f'(x) = \frac{x}{(\ln x)^3}\)
d. \( f'(x) = \frac{1}{x (\ln x)(\ln(\ln x))}\)
e. \( f'(x) = \frac{\ln x}{x^3}\)
2. \(g(x) = \sin(\pi x)\)
a. \(g'(x) = \cos(\pi x)\)
b. \(g'(x) = \cos(\pi)\)
c. \(g'(x) = x\cos(\pi x)\)
d. \(g'(x) = \pi \cos(\pi x)\)
e. \(g'(x) = 0\)
3. \(f(x) = \sin(x^2 + 2^x)\)
a. \( f'(x) = \cos(x^2+2^x)\)
b. \( f'(x) = \cos(x^2+2^x)(2x + (\ln 2)2^x)\)
c. \( f'(x) = \cos(2x + x2^{(x-1)})\)
d. \( f'(x) = \cos(2x + (\ln 2)2^x)\)
e. \( f'(x) = \sin(x^2 + 2^x)(2x + x 2^{(x-1)})\)
4. \(f(x) = 2^{2x}\)
a. \(f'(x) = (2x) 2^{(2x - 1)}\)
b. \(f'(x) = (2x) 2^{2x}\)
c. \(f'(x) = x 2^{2x}\)
d. \(f'(x) = (\ln 2) 2^{2x}\)
e. \(f'(x) = (2 \ln 2) 2^{2x}\)
5. \(h(x) = \frac{e^{(\sin x)}}{x}\)
a. \(h'(x) = \frac{e^{(\sin x)}(\cos x) x - e^{(\sin x)}}{x^2}\)
b. \(h'(x) = e^{(\sin x)}\)
c. \(h'(x) = \frac{e^{(\sin x)} - e^{(\sin x)}(\cos x)x}{x^2}\)
d. \(h'(x) = e^{(\sin x)} - e^{(\sin x)}(\cos x) x\)
e. \(h'(x) = \frac{e^{(\sin x)} - e^{(\cos x)}x}{x^2}\)
In Problems 6 - 9 assume that the height, \(h\), of a hot-air balloon in meters, \(t\) minutes after it is launched is given by the function \( h(t) = t^3 - 8t^2 + 16 t\)
6. What is the height of the balloon after 2 minutes?
a. 2 m
b. 4 m
c. 8 m
d. 16 m
e. 32 m
7. What is the average vertical velocity of the balloon for the first two minutes of flight?
a. 2 m/minute
b. 4 m/minute
c. 8 m/minute
d. 16 m/minute
e. 32 m/minute
8. What is the vertical velocity of the balloon two minutes after launch?
b. -2 m/minute
c. -4 m/minute
d. 8 m/minute
e. -8 m/minute
9. What is the vertical acceleration of the balloon one minute after launch?
a. -10 m/minute2
b. 10 m/minute2
c. -12 m/minute2
d. -12 m/minute2
e. 22 m/minute2